Correct option is (b) ±796 Hz
Easiest explanation: Resonant Frequency, FR = \(\frac{1}{2π\sqrt{LC}} \)
= \(\frac{1}{6.28\sqrt{(5 × 10^{-3})(0.02 × 10^{-6})}}\)
= \(\frac{1}{6.28\sqrt{10^{-10}}}\)
= \(\frac{1}{6.28 × 10^{-5}}\) = 15.9 kHz.
Inductive Reactance, XL = 2πfL = (6.28) (15.92 × 10^3)(5 × 10^-6)
= 0.5 kΩ
∴ Quality factor Q = \(\frac{X_L}{R} = \frac{0.5 kΩ}{50}\) = 10
∴ ∆F = \(\frac{f}{Q} = \frac{15.9 kHz}{10}\) = 1.592 kHz
∴ Bandwidth = \(\frac{∆F}{2}\) = ±796 Hz.