Correct answer is (a) 25, 2
The explanation is: We know that, the bandwidth is, B = w2 – w1 = 2 krad/s
Also, B = \(\frac{R}{L} = \frac{2}{10^{-3}}\) = 2 krad/s
Also, the quality factor is given by, Q = \(\frac{w_0}{B}\)
Or, Q = \(\frac{w_0}{B} = \frac{50}{2}\) = 25.