Correct option is (b) 5 mH
To explain: LEFF = L1 + L2 ± 2M (when the two coils are connected in series)
Now, L1 = L2 = L
∴ LEFF = 2L ± 2M
Or, 2L + 2M = 20
Or, 2L – 2M = 12
∴ L = 8, M = 2
Now, to get maximum value in parallel connection,
LMAX = \(\frac{(L+M)(L+M)}{2L+2M}\)
= \(\frac{(8+2)(8+2)}{(16+4)}\)
= \(\frac{100}{20}\) = 5 mH.