Correct choice is (d) P decreases 4 times
Explanation: I1 = \(\frac{V}{\sqrt{R^2+ ω_1^2 L^2}} = \frac{V}{ω_1 L}\)
For a high current coil, ωL >> R
I2 = \(\frac{V_1}{2ω_1 L} = \frac{I_1}{2}\)
∴ P2 = R (\(\frac{I_1}{2}\))^2 = \(\frac{P_1}{4}\)
Therefore, P decreases 4 times.