Question

After taking the inverse transform of current in the circuit shown below, the value of current is?

(a) i=(V/C)e^-t/R

(b) i=(V/C)e^-t/RC

(c) i=(V/R)e^-t/RC

(d) i=(V/R)e^-t/R

This question was posed to me in an online interview.

This question is from Circuit Elements in the S-Domain in division Application of the Laplace Transform in Circuit Analysis of Network Theory

Answer 1

The correct choice is (c) i=(V/R)e^-t/RC

The best explanation: We had assumed the capacitor is initially charged  to Vo volts. By taking the inverse transform of the current, we get i=(V/R) e^-t/RC.