Right choice is (b) Sum of h-parameter matrices
For explanation: The forward short circuit current gain is given by,
h21 = \(\frac{I_2 (s)}{I_1 (s)}\), when V2 = 0
So, when the two networks are connected in series parallel combination,
[h11, h12; h21, h22] = [h’11 + h’11, h’12 + h’12; h’21 + h’21, h’22 + h’22]
So, h21 of total network will be sum of h parameter matrices.