Question

Consider a circuit having a charge of 600 C, which is delivered to 100 V source in a 1 minute. The value of Voltage source V is ___________

(a) 30 V

(b) 60 V

(c) 120 V

(d) 240 V

This question was addressed to me in an interview for job.

The query is from Advanced Problems on Two Port Network topic in division Two-Port Networks of Network Theory

Answer 1

Right answer is (d) 240 V

Easiest explanation: In order for 600 C charges to be delivered to 100 V source, the electric current must be in reverse clockwise direction.

Now, I = \(\frac{dQ}{dt}\)

= \(\frac{600}{60}\) = 10 A

Applying KVL we get

V1 + 60 – 100 = 10 × 20 ⇒ V1 = 240 V.