The correct option is (b) 6.67%
The best explanation: RT = \(\frac{V_T}{I_T}\)
VT = 200 V, IT = 10 A
So, RT = 20 kΩ
Resistance of voltmeter,
RV = 1000 × 300 = 300 kΩ
Voltmeter is in parallel with unknown resistor,
RX = \(\frac{R_T R_V}{R_T – R_V} = \frac{20 ×300}{280}\) = 21.43 kΩ
Percentage error = \(\frac{Actual-Apparent}{Actual}\) × 100
= \(\frac{21.43-20}{21.43}\) × 100 = 6.67%.