Question

The expression of current flowing in a series equalizer is?

(a) Vmax/√((Ro)^2+(X1)^2)

(b) Vmax/√((2Ro)^2+(X1)^2)

(c) Vmax/√((2Ro)^2+(2X1)^2)

(d) Vmax/√((Ro)^2+(2X1)^2)

I got this question at a job interview.

Enquiry is from Series Equalizer topic in portion Filters and Attenuators of Network Theory

Answer 1

The correct option is (c) Vmax/√((2Ro)^2+(2X1)^2)

The best explanation: When the equalizer is connected, the expression of current flowing in a series equalizer is I1 = Vmax/√((2Ro)^2+(2X1)^2) where Vmax is voltage applied to the network and Ro is resistance of the load as well as source and 2X1 is the reactance of the equalizer.