Question

What is the power at the load of a shunt equalizer?

(a) [(Vmax^2 X1^2)/(Ro(Ro^2+X1^2))]

(b) [(Vmax^2 X1^2)/(2Ro(Ro^2+X1^2))]

(c) [(Vmax^2 X1^2)/(3Ro(Ro^2+X1^2))]

(d) [(Vmax^2 X1^2)/(4Ro(Ro^2+X1^2))]

I got this question in an interview for job.

The origin of the question is Shunt Equalizer in section Filters and Attenuators of Network Theory

Answer 1

Correct choice is (d) [(Vmax^2 X1^2)/(4Ro(Ro^2+X1^2))]

Explanation: The power at the load of a series equalizer is P=((Vmax jX1)/(2Ro(Ro+jX1)))^2 Ro =[(Vmax^2 X1^2)/(4Ro(Ro^2+X1^2))].