Right choice is (d) 125/4
To explain: Since there is an extra term in the numerator compared to the denominator and also an s term in the denominator, the two poles exists at 0 and infinity. Therefore the network consists of first element and last element.
By taking the partial fraction expansion of Z(s), we obtain A=5(s^2+4)(s^2+25)/((s^2+16))|s=0
=(5×4×25)/16=125/4.