Question

Consider a series RLC circuit having resistance = 1Ω, capacitance = 1 F, considering that the capacitor gets charged to 10 V. At t = 0 the switch is closed so that i = e^-2t. When i = 0.37 A, the voltage across capacitor is _____________

(a) 1 V

(b) 6.7 V

(c) 0.37 V

(d) 0.185 V

This question was addressed to me by my college professor while I was bunking the class.

My question is from Advanced Problems Involving Complex Circuit Diagram in division Network Theory and Complex Circuit Diagram of Network Theory

Answer 1

The correct choice is (b) 6.7 V

To explain I would say: We know that, during discharge of capacitor,

VC = VR

Now, VR = 0.67 X 10 = 6.7 V

So, VC  = 6.7 V.