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The output of the previous question, on passing through “nibble substitution” gets us the output

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The output of the previous question, on passing through “nibble substitution” gets us the output

(a) 3267

(b) 1344

(c) 64C0

(d) CA37

I had been asked this question during an interview.

Enquiry is from The AES Algorthm topic in division Advanced Encryption Algorithm and Block Cipher Operation of Cryptograph & Network Security

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The correct option is (c) 64C0

For explanation I would say: 81AC after passing through the “nibble substitution” round produces an output 64C0. A corresponding substitution is referred to in this step.

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