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The multiplicative inverse of 0x95 in AES where m(x)=x^8+x^4+x^3+x+1 is

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The multiplicative inverse of 0x95 in AES where m(x)=x^8+x^4+x^3+x+1 is

(a) 0x8F

(b) 0xF8

(c) 0x8A

(d) 0xA8

I got this question by my school principal while I was bunking the class.

My question is based upon The AES Algorithm in division Advanced Encryption Algorithm and Block Cipher Operation of Cryptograph & Network Security

1 Answer

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Best answer
Correct choice is (c) 0x8A

Easiest explanation: The multiplicative inverse is 0x8A.

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