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[(a mod n) – (b mod n)] mod n = (b – a) mod n

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[(a mod n) – (b mod n)] mod n = (b – a) mod n

(a) True

(b) False

The question was asked by my school principal while I was bunking the class.

Question is taken from Number Theory in chapter Basic Concepts in Number Theory and Finite Fields of Cryptograph & Network Security

1 Answer

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Best answer
Right choice is (b) False

Easy explanation: The equivalence is false and can be checked by substituting values. The correct equivalence would be [(a mod n) – (b mod n)] mod n = (a – b) mod n.

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