Question

First address of the second subblock –

(a) 14.24.74.192/26

(b) 14.24.74.128/26

(c) 14.24.74.127/28

(d) 14.24.74.67/27

I had been asked this question at a job interview.

This intriguing question originated from Designing Subnets topic in section Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security

Answer 1

Right answer is (b) 14.24.74.128/26

The best explanation: First address = 14.24.74.128/26

First address = (any address) AND (network mask).