Question

The expected workload of generating a collision is of the order of ____________ executions of Whirlpool.

(a) 2^(n/2)

(b) 2^(n-1)

(c) 2^(n)

(d) 2^(2n)

I got this question during an interview.

The query is from Whirlpool Algorithm in division Message Authentication Codes, Whirlpool Algorithm and Key Management and Distribution of Cryptograph & Network Security

Answer 1

The correct answer is (a) 2^(n/2)

The explanation: The expected workload of generating a collision is 2^(n/2).