Question

Signal to quantization noise ratio of a PCM encoder is given by _________

(a) 6.02n + α

(b) 3n + 6.02α

(c) n + 6.02α

(d) 6.02n + α

I got this question by my college director while I was bunking the class.

Origin of the question is Quantization Techniques in chapter Speech Coding of Wireless/Mobile

Answer 1

Correct option is (d) 6.02n + α

Easiest explanation: Signal to quantization noise (SQNR) ratio of a PCM encoder is related to the number of bits, n used for encoding. It follows the following relation, SQNR= 6.02n + α. Here, α = 4.77 dB for peak SQNR and α = 0 dB for average SQNR.