Question

A TDMA system uses 25 MHz for the forward link, which is broken into radio channels of 200 kHz. If 8 speech channels are supported on a single radio channel, how many simultaneous users can be accommodated?

(a) 25

(b) 200

(c) 1600

(d) 1000

I got this question in an international level competition.

This interesting question is from Time Division Multiple Access (TDMA) topic in chapter Multiple Access Techniques for Wireless Communications of Wireless/Mobile

Answer 1

Correct option is (d) 1000

To explain I would say: For a TDMA system that uses 25 MHz for the forward link, which is broken into radio channels of 200 kHz. If 8 speech channels are supported on a single radio channel, 1000 simultaneous users can be accommodated as N = (25 MHz)/(200 kHz/8).