Question

A body moves from point A (3,6) to point B (11,12) to point C (15,15). What is the average speed of the body along the given path if the total time taken is 100s?

(a) 0.15 units/s

(b) 1.5 units/s

(c) 15 units/s

(d) 0.0015 units/s

I have been asked this question in a national level competition.

My question is based upon Motion in a Plane with Constant Acceleration in portion Motion in a Plane of Physics – Class 11

Answer 1

Correct option is (a) 0.15 units/s

Best explanation: The distance between A and B is 10 units. The distance between B and C is 5 units. Hence, the total distance is 15 units. The total time taken is 100 s. Average speed = total distance/total time taken = 15/100 = 0.15 units/s.