Question

Consider a block of mass 9.81kg on an inclined surface of the coefficient of friction 0.15 and angle of inclination 30 degrees. What will be its acceleration on the inclined plane if acceleration due to gravity is 9.81 m/s^2?

(a) 3.63 m/s^2

(b) 4.63 m/s^2

(c) 9.81 m/s^2

(d) 10 m/s^2

I have been asked this question in class test.

My doubt is from Friction topic in section Work, Energy and Power of Physics – Class 11

Answer 1

The correct answer is (d) 10 m/s^2

Explanation: a = g (sin θ – u cos θ)

a = 9.81 (sin(30) – 0.15 cos(30))

 = 9.81 x (0.5 – 0.13)

 = 3.63 m/s^2.