Question

A force F = x + 1 N acts on a particle in x direction. What is the work done from x = 2m to 5 m?

(a) 10.5 J

(b) 14.5 J

(c) 13.5 J

(d) 0.5 J

This question was addressed to me during an internship interview.

My question is taken from Work Done by a Variable Force in section Work, Energy and Power of Physics – Class 11

Answer 1

Correct option is (c) 13.5 J

The explanation: Work done is given by W = \(\int_{x1}^{x2}\)F * dx. So, W = \(\int_{2}^{5}\)(x + 1) * dx = [(5^2/2 + 5) – (2^2/2+2)] = 13.5.