Question

A body is moving with a constant acceleration of 11î + 2ĵ, starting from î + ĵ. What will be the position of the body after 10s?

(a) 551î + 101ĵ

(b) 550î + 100ĵ

(c) 100î – 550ĵ

(d) 550î – 550ĵ

I had been asked this question by my college director while I was bunking the class.

I need to ask this question from Motion in a Plane in section Motion in a Plane of Physics – Class 11

Answer 1

Right choice is (a) 551î + 101ĵ

To explain: The body’s displacement is given by s = (1/2)at^2. Therefore, after putting in the values, we get, s = (1/2)(11î + 2ĵ)*10^2 = 550î + 100ĵ. The body initially starts from î + ĵ. Hence, the final position is = initial position + displacement = 551î + 101ĵ.