Question

A bag of mass 1000 g, projected at an angle of 90° from the ground with an initial velocity of 5 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum height attained?

(a) 1.25 m

(b) 3.0 m

(c) 1.5 m

(d) 2.0 m

The question was asked in class test.

This question is from Simple Projectile Motion in chapter Motion in a Plane of Physics – Class 11

Answer 1

The correct option is (a) 1.25 m

The best I can explain: The formula for maximum height is h = (v sinθ)^2/2g. Here, v = 5, θ = 90°, g = 10. Hence, on solving we will get the maximum height attained as 1.25 m. The maximum height can alternatively be found by simply using equations of motion as this bag is thrown vertically upwards.