Question

A force is applied on a cube of side 3m. Another force, double the magnitude of the previous force is applied on a cube of 1m. What is the ratio of pressure on the first cube (P) to the pressure on the second cube (P’)?

(a) 1/9

(b) 18

(c) 1/18

(d) 1/2

This question was addressed to me during an interview for a job.

The question is from Fluids Mechanical Properties Pressure topic in section Mechanical Properties of Fluids of Physics – Class 11

Answer 1

Correct option is (c) 1/18

The explanation: P = F/3^2

P = F/9

P’ = 2F/1^2

P’ = 2F/1

P/P’ = (F/9)/(2F/1)

 = 1/18.