Correct choice is (a) 4√2m/s
The explanation is: F = -dU/dx = 8 – 2x.
Particle starts from x=0, so force will increase its speed till force becomes zero at x=4.
Let acceleration be ‘a’.
a = dv/dt = v dv/dx.
And a = F/m = F/1 = 8-2x.
adx = vdv. Now, integrate both sides. The limits of dx will be 0 to 4 and the limits of dv will be 0 to v.
(8x – x^2)0^4 = v^2/2.
∴ v = 4√2 m/s.