The correct answer is (c) 2π/3
Best explanation: In the given equation the phase is 3x-2t+π/2.
This is repeated after every 2π.
∴ sin( 3x-2t+π/2) +2nπ = sin( 3x-2t+π/2). We can consider the case at t=0, sin(3x+π/2) = sin(3x+π/2+2nπ) OR cos(3x) = cos(3x+2nπ) ∴ n = 1 for minimum difference. Minimum distance can be found from kx = 2π OR x = 2π/k = 2π/3.