Question

A closed container contains 0.6m^3 of neon gas at 200K temperature and 1.3*10^5Pa. Find the rise in temperature when 8360 J of heat is supplied to it. The molar heat capacity of neon at constant volume is 3.2calK^-1mol^-1. Assume the container doesn’t expand on heating.

(a) 13.3K

(b) 15.8K

(c) 13.9K

(d) 15K

The question was posed to me by my college director while I was bunking the class.

This is a very interesting question from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer 1

Correct choice is (a) 13.3K

For explanation I would say: no. of moles of neon gas = pV/RT

= (1.3*10^5*0.6) / (8.31*200)

= 46.9 moles ≅ 47 moles

ΔQ = nCVΔT                                                                                                                                                                                      ΔT = ΔQ/nCV

= (8360/4.18) / (47*3.2)

= 13.3K.