Question

What will be the value of temperature of hot reservoir in a carnot cycle, if the temperature of cold reservoir is 25°C, heat absorbed from hot reservoir is 12J and heat rejected to cold reservoir is 4J?

(a) 684K

(b) 333.33K

(c) 894K

(d) 433.33K

I got this question in an interview for job.

My enquiry is from Thermodynamics in section Thermodynamics of Physics – Class 11

Answer 1

Correct answer is (c) 894K

The best I can explain: For a carnot cycle: Q2/Q2 = T2/T1.

T2 = 12/4 * 298 = 894K.