Correct option is (a) 20.62Hz
The best explanation: As the air is moving, we can solve this question from the air’s frame of reference. From the air’s frame of reference, the observer will be going towards the observer at 2m/s and the source will be coming towards the observer at 10-2 = 8m/s.
F = f(v+v0)/(v+v8)
= 20(330+2)/(330-8)
= 20*332/322 = 20.62Hz.