Question

A Timeout Rule is initialized by ____________

(a) @Rule public Timeout object = new Timeout()

(b) @Rule  public Timeout object = Timeout.seconds()

(c) public Timeout object = Timeout.seconds()

(d) public Timeout object = new Timeout()

This question was addressed to me in an online interview.

This intriguing question originated from Timeout Testing topic in division Mastering JUnit of JUnit

Answer 1

Correct option is (b) @Rule  public Timeout object = Timeout.seconds()

For explanation: The correct way to initialise a Timeout Rules is using the Timeout.seconds() function.