Question

What will be the grouping of cells when the current in the circuit is \(\frac {ne}{(R + nr)}\)?

(a) Parallel grouping

(b) Series grouping

(c) Mixed grouping

(d) When there is no grouping

I had been asked this question by my school teacher while I was bunking the class.

The query is from Current Electricity topic in chapter Current Electricity of Physics – Class 12

Answer 1

The correct choice is (b) Series grouping

For explanation: When n identical cells, each of emf ‘e’ and internal resistance ‘r’ are connected to the external resistance ‘R’ in series, its called series grouping. In series grouping eeq = ne and req = nr Therefore, current in the circuit (I) = \(\frac {ne}{(R + nr)}\).