The correct answer is (b) 1.125*10^12V
The explanation: In the SI system, electric potential due to a point charge at a distance r is \(\frac {q}{4\pi \varepsilon r}\)=9*10^9*\(\frac {q}{r}\). Substituting the values, we get potential=9*10^9*\(\frac {10}{0.08}\)V=1.125*10^12V. Though in practice, this huge value of electric potential is not present.