Right option is (a) [M L^3 T^-3 I^-1]
The best I can explain: Electric flux=electric field intensity* area. The dimension of field intensity is [M L T^-3 I^-1] and the dimension of the area is [L^2]. Therefore, the dimension of flux = [M L^3 T^-3 I^-1]. This can also be justified that flux=potential*length. By putting the dimensions of potential and length, we can get the same result.