The correct answer is (c) 20 m to 120 m
Easy explanation: Maximum wavelength in the band will correspond to the lowest frequency:
c=fminλmax
λmax=\(\frac {c}{f_{min}}=\frac {3\times 10^8}{2.5\times 10^6}\)=120 m
Minimum wavelength in the band will correspond to the highest frequency:
c=fmaxλmin
λmin=\(\frac {c}{f_{max}} =\frac {3\times 10^8}{15 \times 10^6 }\)=20 m
Therefore, the corresponding wavelength band is 20 m to 120 m.