Question

Calculate the torque on a 500 turn rectangular coil of length 20 cm and breadth 10 cm, carrying a current of 30 A, when placed making an angle of 60^o with a magnetic field of 0.5 T?

(a) 625 Nm

(b) 125 Nm

(c) 75 Nm

(d) 25 Nm

This question was posed to me in class test.

The above asked question is from Torque on Current Loop & Magnetic Dipole in section Moving Charges and Magnetism of Physics – Class 12

Answer 1

The correct option is (c) 75 Nm

Explanation: Torque = NIBA cosθ [Angle between field and plane of coil].

Torque = 500 × 30 × 0.5 × 200 × 10^-4 × cos (60)

Torque =75 Nm.

Therefore, the torque is 75 Nm.