The correct choice is (b) By connecting a low resistance shunt in parallel to the galvanometer
Easiest explanation: A galvanometer can be converted into an ammeter of given range by connecting suitable low resistance S called shunt in parallel to the given galvanometer, whose value is given by:
S = \( [ \frac {I_g}{(I – I_g)} ] \)G
Where Ig is the current for full scale deflection of galvanometer, I is the current to be measured by the galvanometer and G is the resistance of galvanometer.