The correct choice is (c) 0.017
To explain: Given: χm1 = 0.0085; T1 = -80^0 C = -80 + 273 = 193 K; T2 = -180^0 C = -180 + 273 = 93 K
χm ∝ \(\frac {1}{T}\)
\(\frac {\chi_{m2}}{\chi_{m1}} \, = \, \frac {T_1}{T_2}\)
\(\frac {\chi_{m2}}{0.0085} \, = \, \frac {193}{93}\)
χm2 = \(\frac {193 \, \times \, 0.0085}{93}\)
χm2 = 0.017