Right choice is (c) ∆Q = \(\frac {\triangle \Phi_B}{r}\)
Easy explanation: There is a relationship between the charge flow through the circuit and the change in the magnetic flux. According to Faraday’s Law, the induced emf is given by:
|ε|=\( \frac {\triangle \Phi_B}{\triangle t}\)
But, |ε|=Ir=\(( \frac {\triangle Q}{\triangle t} ) \)r
Therefore, the relation is given by:
∆Q = \(\frac {\triangle \Phi_B}{r}\)