Question

Determine the self-inductance of a coil, which has a magnetic flux of 50 milliwebers that is produced when a current of 5 A flows through it?

(a) 1 × 10^-2 Wb

(b) 1 × 10^-3 Wb

(c) 100 Wb

(d) 1 × 10^3 Wb

The question was posed to me in an internship interview.

Enquiry is from Electromagnetic Inductance in division Electromagnetic Induction of Physics – Class 12

Answer 1

Right choice is (a) 1 × 10^-2 Wb

The explanation is: Self-inductance = \(\frac {Magnetic \, flux}{Current}\)

Self-inductance = \(\frac {50 \times 10^{-3}}{5}\)

Self-inductance = 1 × 10^-2 Wb