Question

A capacitor of capacitance 10 μF is connected to an oscillator giving an output voltage, E = 10 sin ωt volt. If ω = 10 rad s^-1, find the peak current in the circuit.

(a) 197 mA

(b) 1 mA

(c) 179 mA

(d) 5 mA

I had been asked this question in an online interview.

Enquiry is from AC Voltage Applied to a Capacitor in division Alternating Current of Physics – Class 12

Answer 1

Right option is (b) 1 mA

The best I can explain: I0 = \(\frac {E_0}{(\frac {1}{\omega C})}\)

I0 = ωCE0.

I0 = 10 × 10 × 10^-6 × 10

I0 = 10^-3A = 1 mA.