Correct option is (a) 450 ohms
To elaborate: Potential gradient along the potentiometer wire = \(\frac {potential \, difference \, along \, wire}{length \, of \, wire}\).
0.5 × 10^-3 = I × \(\frac {50}{1000}\)
I = 0.5 × 10^-3 × \(\frac {1000}{50}\)
I = \(\frac {1}{100}\)
So, \(\frac {5}{(50 + R)} = \frac {1}{100}\)
R + 50 = 500
R = 450 ohms
Therefore, the resistance unplugged in the box is 450 ohms.