Question

Based on the Bohr model, what is the minimum energy required to remove an electron from the ground state of Be atom? (Given: Z = 4)

(a) 1.63 eV

(b) 15.87 eV

(c) 30.9 eV

(d) 217.6 eV

I have been asked this question during an internship interview.

This interesting question is from Alpha-Particle Scattering and Rutherford’s Nuclear Model of Atom topic in portion Atoms of Physics – Class 12

Answer 1

Right answer is (d) 217.6 eV

To elaborate: The equation is given as:

En = \(\frac {-13.6 Z^2}{n^2}\) eV

En = \(\frac {-13.6 \times 16 }{ 1 }\)

En = -217.6 eV

Hence the ionization energy for an electron in the ground state of Be atom is 217.6 eV.