Question

Calculate the value of peak reverse voltage (P.I.V.) if the full-wave rectifier has an alternating voltage of 300 V.

(a) 849 V

(b) 800 V

(c) 750 V

(d) 870 V

I have been asked this question by my school principal while I was bunking the class.

This is a very interesting question from Semiconductor Electronics topic in division Semiconductor Electronics : Materials, Devices and Simple Circuits of Physics – Class 12

Answer 1

Right answer is (a) 849 V

Easy explanation: Given: Erms = 300 V

The required equation is ➔ P.I.V. = 2 × E0 or P.I.V. = 2√2 × Erms

P.I.V. = 2√2 × 300 V

P.I.V. = 848.52 V ≈ 849 V.