The correct answer is (d) 27:1
To elaborate: Given: R1 = R0 (A1)^1/3 and R2 = R0 (A2)^1/3
\(\frac {R1}{R2} = (\frac {A1}{A2} ) ^{\frac {1}{3}} \) or \( \frac {A1}{A2} = (\frac {R1}{R2} )^3 = (\frac {1}{3} )^3 \)
\( \frac {A1}{A2} = \frac { 1}{27}\)
So, the ratio of their masses is given as:
\( \frac {m1}{m2} = \frac { 1}{27}\)
According to the principle of conservation of momentum, the magnitude of p1 = magnitude of p2
m1v1 = m2v2
\( \frac {v1}{v2} = \frac {m2}{m1} = \frac {27}{1}\) = 27:1.