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8 mol/L

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in Chemistry – Class 11 by (148k points)
8 mol/L

(a) 0.88 mol/L

(b) 1.3 mol/L

(c) 1.05 mol/L

The question was asked in an international level competition.

My doubt stems from Stoichiometry and Stoichiometric Calculations in portion Chemistry Basic Concepts of Chemistry – Class 11

1 Answer

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Correct answer is (b) 1.3 mol/L

For explanation: When two solutions are combined, the resultant molarity is M1V1 + M2V2/V1 + V2. Consider M1 = 1.3, M2 = 0.8, V1 = 100ml and V2 = 500ml. Now resultant molarity = 1.3(100) + 0.8(500)/100 + 500 = 0.88 mol/L.

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