Question

In case of the decomposition of hydrogen molecule into two hydrogen atoms, the enthalpy of atomization is same as the _________

(a) bond dissociation enthalpy

(b) enthalpy of formation

(c) enthalpy of combustion

(d) enthalpy of sublimation

The question was posed to me during an interview for a job.

My enquiry is from Thermodynamics in chapter Thermodynamics of Chemistry – Class 11

Answer 1

Right option is (a) bond dissociation enthalpy

For explanation: In case of the decomposition of hydrogen molecule the enthalpy is the same as enthalpy of atomization as well as bond dissociation enthalpy because the bond association enthalpy refers to the breakage of H-H Bond. So that two hydrogen atoms are formed whereas enthalpy of atomization is the breakage of hydrogen molecules in order to form two atoms.