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for the reaction H2(g) + Br2(g) ↔ 2HBr(g) the equilibrium constant is given as 0.04 then what is the equilibrium constant for the reaction 2HBr(g) ↔ H2(g) + Br2(g)?

(a) 0.04

(b) 4

(c) 25

(d) 100

The question was posed to me in homework.

My question comes from Law of Chemical Equilibrium and Equilibrium Constant topic in chapter Equilibrium of Chemistry – Class 11

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Right answer is (c) 25

The explanation: In a chemical reaction if the equilibrium constant for a backward reaction is given by k then the equilibrium constant for the forward reaction is given by 1/k, so your the resultant answer becomes 1/0.04 = 25.

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