Right answer is (d) 7.48
Easiest explanation: We know that the pH of the solution of a weak acid and a weak base is given by 1/2pKW + 1/2pKa – 1/2pKb. So pH = 7 + \(\frac{1}{2}\)[4.2 – 3.24]; pH = 7 + 0.48 = 7.48, we get this by substituting acetic acid’s pKa as 4.2 and ammonium hydroxide pKb as 3.24.