Question

If Ksp of a salt A2B3 is given by 1 x 10^-25. Then find the solubility of the salt?

(a) 10^-3

(b) 10^-4

(c) 10^-5

(d) 10^-8

I got this question during a job interview.

Query is from Solubility Equilibria of Sparingly Soluble Salts topic in portion Equilibrium of Chemistry – Class 11

Answer 1

Right answer is (c) 10^-5

Explanation: For the salt AxBy, (AxBy = xA^y+ + yB^x+), the solubility of a sparingly soluble salt is given by x^x.y^y.s^x+y. Ksp = x^x.y^y.s^x+y, where x = 2 and y = 3; Ksp = 108S5 = 1 x 10^-25. S = 10^-5. The solubility of the salt is given by 10^-5.